Prac1 Q1

Published: 28/10/2024
Last modified: 29/10/2024

Simplify:

$$ \left(\frac{\left(75x^3y^{-2}z\right)^2}{3z^9y^4x^2}\right)\left(\frac{\left(5xyz\right)}{\left(15x^2z^{-1}\right)}\right)^{-1} $$

BOMDAS

Brackets
$\left(75x^3y^{-2}z\right)^2$